AQA A-Level Organic Chemistry 3.3.9 Carboxylic Acids & Derivatives Acyl Chlorides & Acid Anhydrides
3.3.9

Acyl Chlorides & Acid Anhydrides

Structure and reactivity, addition-elimination mechanisms, and industrial comparisons.

Acyl chlorides and acid anhydrides are carboxylic acid derivatives that are highly reactive because of the presence of a carbonyl group (\( \text{C}=\text{O} \)) bonded to a good leaving group. In this lesson, we study their structures, their characteristic nucleophilic addition-elimination mechanisms, and compare their industrial utility in manufacturing processes.

🔑 Key Principle

The reactivity of acyl derivatives is governed by the strength of the partial positive charge (\( \delta^+ \)) on the carbonyl carbon and the stability of the leaving group. Acyl chlorides have a highly electron-deficient carbonyl carbon and an excellent leaving group (\( \text{Cl}^- \)), making them extremely reactive.

Structure and Reactivity Comparison

Both families contain the acyl group (\( \text{R-C}(=\text{O})- \)) but differ in what is attached to it:

Acyl Chloride

A derivative of a carboxylic acid where the hydroxyl group is replaced by a chlorine atom, having the general formula \( \text{RCOCl} \).

Acid Anhydride

A derivative formed by condensation of two carboxylic acid molecules, having the general formula \( \text{RCO-O-COR} \).

Because the chlorine atom in acyl chlorides and the carboxylate oxygen in acid anhydrides are highly electronegative, they withdraw electron density from the carbonyl carbon. This increases its partial positive charge (\( \text{C}^{\delta+} \)), making it highly electrophilic and susceptible to attack by nucleophiles. Since chlorine is a better leaving group than a carboxylate group, acyl chlorides react much more vigorously than acid anhydrides.

The Nucleophilic Addition-Elimination Mechanism

Acyl chlorides and acid anhydrides react with nucleophiles via a two-stage nucleophilic addition-elimination mechanism. The pathway has three steps:

  1. Nucleophilic Addition: The nucleophile attacks the \( \text{C}^{\delta+} \) carbon, breaking the \( \text{C}=\text{O} \) \( \pi \)-bond and forming a tetrahedral intermediate with a negative charge on the oxygen.
  2. Elimination: The lone pair on the oxygen reforms the \( \text{C}=\text{O} \) double bond, ejecting the leaving group (\( \text{Cl}^- \) or \( \text{RCOO}^- \)).
  3. Deprotonation: If the nucleophile was neutral (e.g. water, alcohol, or amine), the positive charge on the nucleophilic atom is removed by losing an \( \text{H}^+ \) ion.
Nucleophilic Addition-Elimination Mechanism Mechanism: Ethanoyl Chloride + Methanol Step 1: Addition C δ+ H₃C Cl O δ− O H₃C H Step 2: Intermediate C H₃C Cl O O + H Step 3: Products C H₃C O O CH₃ + HCl

Reactions of Acyl Chlorides and Acid Anhydrides

You must know the four primary reactions for both functional groups, using ethanoyl chloride and ethanoic anhydride as model compounds:

Nucleophile Reaction with Ethanoyl Chloride Reaction with Ethanoic Anhydride Observations/Products
Water (\( \text{H}_2\text{O} \)) \[ \text{CH}_3\text{COCl} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{COOH} + \text{HCl} \] \[ (\text{CH}_3\text{CO})_2\text{O} + \text{H}_2\text{O} \rightarrow 2\text{CH}_3\text{COOH} \] Chloride reaction is violent at room temperature; gives white, misty fumes of \( \text{HCl} \). Anhydride reaction is slow. Both yield carboxylic acids.
Alcohols (\( \text{R'OH} \)) \[ \text{CH}_3\text{COCl} + \text{R'OH} \rightarrow \text{CH}_3\text{COOR'} + \text{HCl} \] \[ (\text{CH}_3\text{CO})_2\text{O} + \text{R'OH} \rightarrow \text{CH}_3\text{COOR'} + \text{CH}_3\text{COOH} \] Yields esters. Chloride reaction is rapid, yielding misty fumes of HCl. Anhydride requires warming.
Ammonia (\( \text{NH}_3 \)) \[ \text{CH}_3\text{COCl} + 2\text{NH}_3 \rightarrow \text{CH}_3\text{CONH}_2 + \text{NH}_4\text{Cl} \] \[ (\text{CH}_3\text{CO})_2\text{O} + 2\text{NH}_3 \rightarrow \text{CH}_3\text{CONH}_2 + \text{CH}_3\text{COONH}_4 \] Yields a primary amide (ethanamide) and a salt. Violent reaction; white smoke of ammonium salt is observed.
Primary Amines (\( \text{R'NH}_2 \)) \[ \text{CH}_3\text{COCl} + 2\text{R'NH}_2 \rightarrow \text{CH}_3\text{CONHR'} + \text{R'NH}_3\text{Cl} \] \[ (\text{CH}_3\text{CO})_2\text{O} + 2\text{R'NH}_2 \rightarrow \text{CH}_3\text{CONHR'} + \text{CH}_3\text{COONH}_3\text{R'} \] Yields an N-substituted (secondary) amide and an alkylammonium salt.
📝 AQA Examiner Tip

Notice that reactions with ammonia and primary amines require two moles of the nitrogen nucleophile. The first mole acts as the nucleophile to form the amide, while the second mole acts as a base to neutralise the acidic by-product (\( \text{HCl} \) or \( \text{CH}_3\text{COOH} \)), forming a salt.

Industrial Advantages: Ethanoic Anhydride vs Ethanoyl Chloride

In industry, ethanoic anhydride is preferred over ethanoyl chloride for acylating reactions, such as the manufacture of aspirin from salicylic acid:

✏️ Worked Example: Aspirin Synthesis
Write the equation for the synthesis of aspirin (acetylsalicylic acid) from salicylic acid (2-hydroxybenzoic acid) using ethanoic anhydride. Identify the by-product.

Solution:

Salicylic acid has a phenolic hydroxyl group (\( \text{-OH} \)) that is acylated by ethanoic anhydride:

\[ \text{HOC}_6\text{H}_4\text{COOH} + (\text{CH}_3\text{CO})_2\text{O} \rightarrow \text{CH}_3\text{COOC}_6\text{H}_4\text{COOH} + \text{CH}_3\text{COOH} \]

The organic product is aspirin. The by-product is ethanoic acid.

Industry avoids ethanoyl chloride for several critical reasons:

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