AQA A-Level Physical Chemistry 3.1.12 Acids & Bases Brønsted-Lowry Theory
3.1.12

Brønsted-Lowry Theory

Understanding proton donors and acceptors, conjugate acid-base relationships, and acid strength.

The concept of acids and bases was historically defined by their physical properties, but modern chemistry uses structural definitions. The most important model for AQA A-Level Chemistry is the Brønsted-Lowry theory, which defines acids and bases entirely in terms of the transfer of hydrogen ions (protons).

Brønsted-Lowry Acid

A species (molecule or ion) that acts as a proton donor, releasing hydrogen ions (H+) in solution.

Brønsted-Lowry Base

A species (molecule or ion) that acts as a proton acceptor, gaining hydrogen ions (H+) from a donor.

🔑 Key Principle

An acid-base reaction always involves a proton transfer. An isolated proton (H+) cannot exist in aqueous solution; it is immediately accepted by a base. In water, H+ binds to a water molecule to form the hydronium ion (H3O+).

Conjugate Acid-Base Pairs

When a Brønsted-Lowry acid loses a proton, it forms a species that is capable of gaining that proton back. This new species is called its conjugate base. Similarly, when a base gains a proton, it forms its conjugate acid.

Every acid-base reaction features two conjugate pairs. For example, when hydrogen chloride dissolves in water:

\( \text{HCl(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{H}_3\text{O}^+\text{(aq)} + \text{Cl}^-\text{(aq)} \)

Proton Transfer and Conjugate Pairs HCl Acid 1 + H2O Base 2 <=> H3O+ Acid 2 + Cl- Base 1 H+ transfer Conjugate Pair 1 (HCl / Cl-) Conjugate Pair 2 (H2O / H3O+)
Conjugate Acid-Base Pair

Two chemical species that differ only by the presence or absence of one transferrable proton, H+.

📝 AQA Examiner Tip

When asked to identify conjugate pairs, remember that the acid of the pair always contains exactly one more H+ ion than its conjugate base. For example, in a pair containing \( \text{H}_2\text{SO}_4 \) and \( \text{HSO}_4^- \), \( \text{H}_2\text{SO}_4 \) is the acid and \( \text{HSO}_4^- \) is the base. Note that \( \text{H}_2\text{SO}_4 \) and \( \text{SO}_4^{2-} \) do not form a conjugate pair because they differ by two protons, not one!

Strong vs. Weak Acids

Acids differ in how easily they donate protons. We classify them as either strong or weak based on their level of dissociation (splitting into ions) in water:

Strong Acid

An acid that dissociates completely in aqueous solution. The position of equilibrium lies entirely to the right: \( \text{HA(aq)} \rightarrow \text{H}^+\text{(aq)} + \text{A}^-\text{(aq)} \).

Weak Acid

An acid that only partially dissociates in aqueous solution. The position of equilibrium lies far to the left, and a reversible equilibrium is set up: \( \text{HA(aq)} \rightleftharpoons \text{H}^+\text{(aq)} + \text{A}^-\text{(aq)} \).

Common strong acids include hydrochloric acid (\( \text{HCl} \)), nitric acid (\( \text{HNO}_3 \)), and sulfuric acid (\( \text{H}_2\text{SO}_4 \)). Common weak acids include carboxylic acids such as ethanoic acid (\( \text{CH}_3\text{COOH} \)) and carbonic acid (\( \text{H}_2\text{CO}_3 \)).

✏️ Worked Example 1
Identify the two conjugate acid-base pairs in the following equilibrium: \[ \text{NH}_3\text{(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{NH}_4^+\text{(aq)} + \text{OH}^-\text{(aq)} \]

Step 1: Track the proton transfer:

We observe that water (\( \text{H}_2\text{O} \)) loses a proton (\( \text{H}^+ \)) to become hydroxide (\( \text{OH}^- \)). Thus, water acts as a proton donor (acid) and hydroxide is its conjugate base.

Ammonia (\( \text{NH}_3 \)) gains a proton to become ammonium (\( \text{NH}_4^+ \)). Thus, ammonia acts as a proton acceptor (base) and ammonium is its conjugate acid.

Step 2: Group the conjugate pairs:

  • Conjugate pair 1: \( \text{NH}_4^+ \) (acid) and \( \text{NH}_3 \) (base).
  • Conjugate pair 2: \( \text{H}_2\text{O} \) (acid) and \( \text{OH}^- \) (base).
✏️ Worked Example 2
Describe the key differences in dissociation behavior when 1.0 mol of hydrogen chloride gas and 1.0 mol of ethanoic acid liquid are added to separate, equal volumes of water.

Step 1: Classify the acids:

Hydrogen chloride (\( \text{HCl} \)) is a strong acid. Ethanoic acid (\( \text{CH}_3\text{COOH} \)) is a weak acid.

Step 2: Describe dissociation:

\( \text{HCl} \) dissociates completely in water. The reaction goes to completion: \( \text{HCl(g)} + \text{H}_2\text{O(l)} \rightarrow \text{H}_3\text{O}^+\text{(aq)} + \text{Cl}^-\text{(aq)} \). The resulting solution contains 1.0 mol dm^-3 of \( \text{H}_3\text{O}^+ \) ions.

\( \text{CH}_3\text{COOH} \) dissociates only partially in water. A reversible equilibrium is established that lies far to the left: \( \text{CH}_3\text{COOH(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{CH}_3\text{COO}^-\text{(aq)} + \text{H}_3\text{O}^+\text{(aq)} \). Typically, only around 1% of the weak acid molecules dissociate, so the concentration of \( \text{H}_3\text{O}^+ \) ions is much lower than 1.0 mol dm^-3 (around 0.004 mol dm^-3).

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