Exam Practice

Topic 3.1.3: Bonding Exam Practice

Test your understanding of ionic, covalent, and metallic bonding, molecular shapes, polarity, and intermolecular forces.

Bonding Exam Practice

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📋 Structured Questions

Complete each question on paper, then check your answers against the mark scheme.

Question 1: Shapes of Molecules (VSEPR)

6 marks

Deduce the shape and bond angle of the following species. Explain your answers in terms of the Valence Shell Electron Pair Repulsion (VSEPR) theory.

(a) PH3 [3]

(b) AlCl4- [3]

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(a) PH3:

  • Phosphorus has 3 bonding pairs and 1 lone pair of electrons around the central atom. [1]
  • Electron pairs repel each other to get as far apart as possible. The lone pair repels more strongly than the bonding pairs, reducing the bond angle. [1]
  • Shape: trigonal pyramidal. Bond angle: 107° (allow 107.0°). [1]

(b) AlCl4-:

  • Aluminium has 4 bonding pairs and 0 lone pairs of electrons around the central atom. (Al has 3 outer electrons, plus 1 from the charge, sharing 4 with Cl). [1]
  • The 4 bonding pairs repel each other equally to get as far apart as possible. [1]
  • Shape: tetrahedral. Bond angle: 109.5°. [1]
Examiner tip: State the number of bonding pairs and lone pairs first. Then, mention the repulsion principle (minimising repulsion / getting as far apart as possible). State the relative strength of lone pair repulsion when explaining PH3.

Question 2: Electronegativity & Intermolecular Forces

7 marks

(a) Define electronegativity. [2]

(b) Explain why the boiling point of water (H2O, Mr = 18.0) is much higher than that of hydrogen sulfide (H2S, Mr = 34.1). [3]

(c) Tetrachloromethane (CCl4) is non-polar, whereas trichloromethane (CHCl3) is polar. Explain this difference in terms of their structures. [2]

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(a)

  • The power of an atom [1]
  • to attract the shared pair of electrons in a covalent bond. [1]

(b)

  • Oxygen is highly electronegative, so water molecules form hydrogen bonds between them. [1]
  • Sulfur is less electronegative, so hydrogen sulfide molecules are held together by weaker permanent dipole-permanent dipole / London forces. [1]
  • Hydrogen bonds are much stronger than dipole-dipole forces and require more thermal energy to break. [1]

(c)

  • CCl4 is highly symmetrical (tetrahedral), so the individual C-Cl bond dipoles cancel each other out, leaving no overall dipole. [1]
  • CHCl3 is non-symmetrical, so the dipoles do not cancel, resulting in a net dipole moment. [1]
Examiner tip: In part (b), always state the types of intermolecular forces present in both substances. A common mistake is saying "hydrogen bonds are broken in water but covalent bonds are broken in H2S". Covalent bonds are never broken during boiling!

Question 3: Structure and Electrical Conductivity

6 marks

Describe the bonding and structure of sodium chloride and graphite. Explain why graphite conducts electricity but sodium chloride only conducts when molten or dissolved in water. [6]

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Indicative content:

  • Sodium Chloride: Giant ionic lattice structure with electrostatic attractions between oppositely charged Na+ and Cl- ions. [1]
  • Graphite: Giant covalent (macromolecular) structure composed of hexagonal layers of carbon atoms, where each carbon is covalently bonded to three others. [1]
  • NaCl conductivity: In the solid state, the ions are fixed in position in the lattice and cannot move. [1] When molten or dissolved in water, the giant lattice breaks, and the ions are free to move and carry charge. [1]
  • Graphite conductivity: Each carbon atom has one delocalised electron (as it only forms 3 bonds). [1] These delocalised electrons are free to move along the hexagonal layers and carry electrical charge in both solid and liquid states. [1]
Examiner tip: Be very careful with terminology. Solid sodium chloride does not conduct because its ions are not free to move. Do not say "electrons are not free to move" for sodium chloride. Conversely, graphite conducts because of delocalised electrons. Clear separation between ions and electrons is crucial for full marks.

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