IB Chemistry 1.4 1.4.5
1.4.5

Molar Concentration (Solutions)

Concentration

\( c = \frac{n}{V} \)

c = concentration (mol dm⁻³)
n = moles (mol)
V = volume (dm³)

Unit Warning

Volume MUST be in dm³ (not cm³). To convert: divide cm³ by 1000.

Standard Solutions & Dilutions

Standard Solution: A solution of accurately known concentration.

Dilutions: When you add water, moles stay the same but volume increases. Use:

\( c_1V_1 = c_2V_2 \)

Titration Calculation

Problem: 25.0 cm³ of 0.100 mol dm⁻³ NaOH is neutralized by 20.0 cm³ of HCl. Calculate the concentration of HCl.

\( NaOH + HCl \rightarrow NaCl + H_2O \) (1:1 ratio)


1. Moles of NaOH: \( n = c \times V = 0.100 \times 0.0250 = 0.00250 \text{ mol} \)

2. Moles of HCl: (1:1 ratio) = 0.00250 mol

3. Concentration of HCl:

\( c = \frac{0.00250}{0.0200} = 0.125 \text{ mol dm}^{-3} \)

Notation and Units

📘 Square Bracket Notation

In IB Chemistry, concentration is often written using square brackets. For example, [HCl] = 0.10 mol dm⁻³ means "the concentration of HCl is 0.10 mol per cubic decimetre".

Converting Between mol dm⁻³ and g dm⁻³

Sometimes concentrations are given in g dm⁻³ rather than mol dm⁻³. To convert:

Concentration (g dm⁻³) = Concentration (mol dm⁻³) × Molar mass (g mol⁻¹)

Example: [NaCl] = 0.50 mol dm⁻³. Molar mass of NaCl = 58.44 g mol⁻¹. Concentration = 0.50 × 58.44 = 29.2 g dm⁻³.

⚠️ Examiner Tip: ppm

Very dilute solutions (e.g. Pollutants in water) may use parts per million (ppm). For aqueous solutions: 1 ppm = 1 mg dm⁻³. This assumes the density of water is approximately 1 g cm⁻³.

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