IB Chemistry Structure 2 2.4 From Models to Materials 2.4.2
2.4.2
Structure 2.4 SL & HL ⏱ ~5 min revision

Position in the Bonding Triangle

van Arkel-Ketelaar triangles: plotting average electronegativity vs electronegativity difference.

IB Understanding

Bonding Triangle Foundation

The position of a compound in the bonding triangle is determined by the relative contributions of the three bonding types to the overall bond.

Placing a Compound on the Triangle

To locate a binary compound on the bonding triangle, you need the electronegativity values (χ) of the two elements from the IB Data Booklet. Calculate two quantities:

Coordinate 1

X-Axis: Average Electronegativity (Σχ / 2)

\[\text{Average } \chi = \frac{\chi_A + \chi_B}{2}\]

A higher average χ shifts the point to the right, toward the covalent corner.

Coordinate 2

Y-Axis: Electronegativity Difference (Δχ)

\[\Delta\chi = |\chi_A - \chi_B|\]

A higher Δχ pushes the point upward, toward the ionic corner.

Bonding Triangle with Example Compounds

2.4.2 Position in the Bonding Triangle - IB | ChemEasy Average Electronegativity → Δ Electronegativity → 0.5 1.5 2.5 3.5 0 1 2 3 METALLIC COVALENT IONIC Na Fe Cl₂ F₂ HCl NaCl CsF SiO₂

Interpreting the Three Regions

Region Average χ Δχ Bonding type Typical properties
Bottom-left Low Low (≈ 0) Metallic Conducts as solid, malleable, lustrous
Bottom-right High Low (≈ 0) Covalent Low melting point (molecular) or very high (network)
Top Medium High Ionic High MP, conducts when molten/dissolved, brittle
Middle Medium-High Medium Polar covalent Properties intermediate between ionic and covalent

Worked Example

Worked Example 1

Plotting Magnesium Oxide (MgO)

From the Data Booklet: \(\chi(\text{Mg}) = 1.31\), \(\chi(\text{O}) = 3.44\)

  • Average \(\chi = (1.31 + 3.44) / 2 = \mathbf{2.38}\)
  • \(\Delta\chi = |1.31 - 3.44| = \mathbf{2.13}\)
  • ∴ MgO is plotted in the ionic region (high \(\Delta\chi\), medium average \(\chi\)).
  • Prediction: High melting point, conducts when molten, brittle, soluble in water.
Worked Example 2

Plotting Hydrogen Fluoride (HF)

From the Data Booklet: \(\chi(\text{H}) = 2.20\), \(\chi(\text{F}) = 3.98\)

  • Average \(\chi = (2.20 + 3.98) / 2 = \mathbf{3.09}\)
  • \(\Delta\chi = |2.20 - 3.98| = \mathbf{1.78}\)
  • ∴ HF sits between the ionic and covalent regions (significant polar covalent character).
  • Prediction: Hydrogen bonding, relatively high boiling point for its size, exists as a liquid at room temperature.
Limitation

van Arkel-Ketelaar Applies to Binary Compounds Only

The IB syllabus states that only binary compounds (compounds of exactly two elements) need to be considered for bonding triangle questions. You do not need to calculate percentage ionic character.

Predicting Properties from Position

The real power of the bonding triangle is being able to predict the physical properties of a substance from where it sits on the diagram.

Exam Strategy

Reading Coordinates from Data Booklet Section 8

When asked to predict properties from a triangle position:

  1. Identify the dominant bonding type from the region (ionic, covalent, or metallic)
  2. Apply the properties you learned in S2.1 (ionic), S2.2 (covalent), or S2.3 (metallic)
  3. Acknowledge any mixed character if the compound falls near a boundary
Key Takeaway

Real Materials Lie Along Gradients

No compound has 100% pure ionic, covalent, or metallic bonding. Even NaCl has some covalent character. The triangle shows a spectrum of bonding. Compounds near the centre or along the edges display intermediate properties. For example, AlCl₃ is classified as ionic but behaves as a covalent dimer when vaporised.

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