IB ChemistryStructure 33.13.1.10

Coloured Complexes

d-orbital splitting, crystal field theory, the colour wheel, and factors affecting colour.

Structure 3.1 HL Extension ⏱️ ~5 min revision

d-Orbital Splitting

In an isolated gaseous transition metal ion, the five d-orbitals are degenerate (equal energy). When ligands bond to the metal, their lone pairs repel the d-electrons unequally, causing the d-orbitals to split into two energy levels.

The energy gap between the two levels is called ΔE

d-Orbital Splitting in an Octahedral Field

d-Orbital Splitting Diagram Free ion 5 degenerate d-orbitals Ligands approach In complex eg (2 orbitals) t2g (3 orbitals) ΔE hf ΔE = hf = hc/λ

How Colour Arises

  1. White light passes through the solution
  2. A d-electron absorbs a photon with the exact energy matching ΔE
  3. The electron is promoted from the lower to the upper d-orbital level
  4. The remaining wavelengths are transmitted; the observed colour is the complementary colour of the absorbed light

The Colour Wheel

Colour Wheel for Complementary Colours Complementary = opposite Violet Blue Cyan Green Yellow Orange Red Magenta

Factors Affecting ΔE and Colour

FactorEffect on ΔEEffect on Colour
Nature of ligandStrong field ligands (CN⁻) → large ΔE; Weak field (Cl⁻, H₂O) → small ΔEDifferent ligands cause different absorption wavelengths
Oxidation stateHigher charge → ligands pulled closer → larger ΔEColour changes with oxidation state
Identity of metalDifferent nuclear charges and configs → unique splittingEach metal produces characteristic colours
Coordination geometryOctahedral and tetrahedral fields split differentlySame metal/ligand but different geometry → different colour
Colourless Complexes

Why d0 and d10 Complexes Are Colourless

Ions with \(\text{d}^0\) (e.g. \(\text{Sc}^{3+}\), \(\text{Ti}^{4+}\)) or \(\text{d}^{10}\) (e.g. \(\text{Zn}^{2+}\), \(\text{Cu}^{+}\)) configurations cannot undergo \(\text{d}\text{--}\text{d}\) transitions: \(\text{d}^0\) has no d-electrons to promote, while \(\text{d}^{10}\) has completely filled d-orbitals with no vacant higher states. These complexes are completely colourless.

Exam Technique

3-Step Formula: "Why Is a Complex Coloured?"

When asked to explain the origin of colour in a transition metal complex, always state the 3 essential marking points:

  1. Ligands cause d-orbitals to split into two sets of non-degenerate energy levels (\(\Delta E\)).
  2. A d-electron absorbs visible light photons matching \(\Delta E = hf = \frac{hc}{\lambda}\) and is promoted to a higher d-orbital (\(\text{d}\text{--}\text{d}\) transition).
  3. The transmitted / observed colour is the complementary colour to the absorbed wavelength (deduced from the colour wheel).
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