IB Chemistry R3.1 R3.1.1
R3.1.1

Bronsted-Lowry Theory

Key Definitions

  • Brønsted-Lowry acid. A proton (H⁺) donor
  • Brønsted-Lowry base. A proton (H⁺) acceptor
  • Conjugate acid-base pair. Two species that differ by exactly one proton
  • Amphiprotic. A substance that can both donate and accept a proton (e.g. H₂O, HCO₃⁻)
  • Amphoteric. A broader term for any species that can react as both acid and base (includes amphiprotic species plus others like Al₂O₃)

Proton Transfer

According to Brønsted-Lowry theory (1923), acid-base reactions involve the transfer of a proton (H⁺) from an acid to a base. In aqueous solutions, free protons do not exist independently. They coordinate with water to form the hydronium ion (H₃O⁺). The notations H⁺(aq) and H₃O⁺(aq) are used interchangeably.

Example 1. Strong acid in water:

HCl(g) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)

HCl donates a proton (acid); H₂O accepts it (base).

Example 2. Weak base in water:

NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

NH₃ accepts a proton (base); H₂O donates one (acid). Note the reversible arrow. NH₃ is a weak base.

Proton Transfer: HCl + H₂O

Diagram: Proton Transfer: HCl + H₂O HCl Acid (donor) + H₂O Base (acceptor) H⁺ Cl⁻ Conj. Base + H₃O⁺ Conj. Acid Conjugate pair 1 Conjugate pair 2

Identifying Conjugate Pairs

A conjugate acid-base pair is two species that differ by exactly one proton. In any acid-base reaction, there are always two conjugate pairs on opposite sides of the equation.

Step-by-Step Method

  1. Identify which reactant loses H⁺ (that's the acid) and which gains H⁺ (that's the base).
  2. Find the conjugate base: remove one H⁺ from the acid and decrease its charge by 1. E.g. H₂SO₄ → HSO₄⁻
  3. Find the conjugate acid: add one H⁺ to the base and increase its charge by 1. E.g. NH₃ → NH₄⁺
  4. Pair them up: Acid ↔ Conjugate Base, Base ↔ Conjugate Acid.

Amphiprotic vs Amphoteric

These terms are often confused but have an important distinction:

All amphiprotic species are amphoteric, but not all amphoteric species are amphiprotic (e.g. Al₂O₃ is amphoteric but has no H atoms to donate).

Examples of Amphiprotic Species

  • Water (H₂O). Donates H⁺ → OH⁻ or accepts H⁺ → H₃O⁺
  • Hydrogencarbonate (HCO₃⁻). Donates H⁺ → CO₃²⁻ or accepts H⁺ → H₂CO₃
  • Hydrogen sulfate (HSO₄⁻). Donates H⁺ → SO₄²⁻ or accepts H⁺ → H₂SO₄
  • Amino acids. The amino group (−NH₂) accepts H⁺; the carboxyl group (−COOH) donates H⁺ → forms a zwitterion

Neutralisation & Acid Reactions

Neutralisation involves the transfer of a proton from an acid to a base, forming a salt and usually water.

Reaction Type Products Example
Acid + Metal hydroxideSalt + WaterHCl + NaOH → NaCl + H₂O
Acid + Metal oxideSalt + WaterH₂SO₄ + CuO → CuSO₄ + H₂O
Acid + CarbonateSalt + Water + CO₂2HCl + CaCO₃ → CaCl₂ + H₂O + CO₂
Acid + HydrogencarbonateSalt + Water + CO₂HCl + NaHCO₃ → NaCl + H₂O + CO₂
Acid + Reactive metalSalt + H₂ (redox!)Mg + 2HCl → MgCl₂ + H₂

Note: Acid + reactive metal is technically a redox reaction (electron transfer), not a neutralisation. Always include state symbols in your exam answers!

⚠️ Common Exam Mistakes

  • Amphoteric ≠ Amphiprotic: Al₂O₃ is amphoteric but not amphiprotic (no H atoms to donate).
  • Forgetting charge adjustments: The conjugate base of H₂PO₄⁻ is HPO₄²⁻, not HPO₄⁻.
  • Misidentifying the base: In NaOH, only the OH⁻ ion is the Brønsted-Lowry base, not the whole molecule.
  • "Neutralisation = pH 7": Not always! The final pH depends on the strengths of the parent acid and base.
  • State symbols: IB mark schemes are strict. Always include (s), (l), (aq), (g).
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