Unit 1: CH01 Syllabus Node

Group 7: The Halogens

Physical trends down Group 7, oxidising displacement reactions, halide reducing ability with H2SO4, silver nitrate testing, and bleach production.

2. Oxidising Ability and Displacement Reactions

Oxidising Agent

An electron acceptor. Halogen atoms gain electrons to form 1- halide ions: \\[ \text{X}_2 + 2e^- \rightarrow 2\text{X}^- \\]

Oxidising ability decreases down Group 7: \(\text{F}_2 > \text{Cl}_2 > \text{Br}_2 > \text{I}_2\). As atomic radius and electron shielding increase, incoming electrons experience weaker electrostatic attraction to the halogen nucleus.

Displacement Reactions

A more reactive halogen will displace a less reactive halide ion from aqueous solution:

  • \(\text{Cl}_2(aq) + 2\text{Br}^-(aq) \rightarrow 2\text{Cl}^-(aq) + \text{Br}_2(aq)\) (Solution turns yellow-orange).
  • \(\text{Cl}_2(aq) + 2\text{I}^-(aq) \rightarrow 2\text{Cl}^-(aq) + \text{I}_2(aq)\) (Solution turns brown).
  • \(\text{Br}_2(aq) + 2\text{I}^-(aq) \rightarrow 2\text{Br}^-(aq) + \text{I}_2(aq)\) (Solution turns brown).

3. Reducing Ability of Halide Ions with Concentrated Sulfuric Acid

Reducing ability increases down Group 7: \(\text{F}^- < \text{Cl}^- < \text{Br}^- < \text{I}^-\). Iodide ions have the largest ionic radius and greatest shielding, so their outer electrons are most easily lost.

Solid Halide Reaction Type Observations Products Formed
NaCl Acid-base only (no redox) Steamy fumes turning moist blue litmus paper red. \(\text{HCl}(g) + \text{NaHSO}_4(s)\)
NaBr Acid-base AND Redox Steamy fumes (\(\text{HBr}\)), red-brown vapour (\(\text{Br}_2\)), choking colourless gas (\(\text{SO}_2\)). \(\text{HBr}, \text{Br}_2, \text{SO}_2\) (Sulfur reduced from +6 to +4)
NaI Strong Redox Steamy fumes (\(\text{HI}\)), black solid / purple vapour (\(\text{I}_2\)), choking gas (\(\text{SO}_2\)), yellow solid sulfur (\(\text{S}\)), rotten egg smell gas (\(\text{H}_2\text{S}\)). \(\text{HI}, \text{I}_2, \text{SO}_2, \text{S}, \text{H}_2\text{S}\) (Sulfur reduced from +6 down to -2)

4. Qualitative Testing with Acidified Silver Nitrate

To identify unknown halide ions in solution:

  1. Add dilute nitric acid (\(\text{HNO}_3\)) to eliminate carbonate (\(\text{CO}_3^{2-}\)) or hydroxide (\(\text{OH}^-\)) ions that would produce false precipitates. Never use hydrochloric acid, as it introduces chloride ions!
  2. Add aqueous silver nitrate (\(\text{AgNO}_3\)): \[ \text{Ag}^+(aq) + \text{X}^-(aq) \rightarrow \text{AgX}(s) \]
  3. Confirm the precipitate by adding dilute and concentrated aqueous ammonia.
Halide Qualitative Identification Flowchart Step 1: Acidify with dilute HNO3, then add aqueous AgNO3 (HNO3 removes interfering carbonate and hydroxide ions) Chloride (Cl-) WHITE ppt (AgCl) Soluble in DILUTE NH3 Solution turns clear Bromide (Br-) CREAM ppt (AgBr) Insoluble in dilute NH3 Soluble in CONC NH3 Iodide (I-) YELLOW ppt (AgI) Insoluble in dilute NH3 INSOLUBLE in CONC NH3

5. Disproportionation Reactions of Chlorine

Disproportionation

A redox reaction in which the same element is simultaneously oxidised and reduced.

Household Bleach Production

Chlorine reacts with cold dilute aqueous sodium hydroxide:

\[ \text{Cl}_2(g) + 2\text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{NaClO}(aq) + \text{H}_2\text{O}(l) \]

Chlorine is simultaneously reduced to -1 in \(\text{NaCl}\) and oxidised to +1 in sodium chlorate(I), \(\text{NaClO}\) (active ingredient in bleach).

Water Purification

Chlorine disinfects drinking water by killing bacteria:

\[ \text{Cl}_2(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{HCl}(aq) + \text{HClO}(aq) \]

Chloric(I) acid (\(\text{HClO}\)) acts as a powerful oxidising disinfectant. In bright sunlight, chloric(I) acid decomposes:

\[ 2\text{Cl}_2(aq) + 2\text{H}_2\text{O}(l) \rightarrow 4\text{HCl}(aq) + \text{O}_2(g) \]

6. Practice Questions

Practice Problem (4 Marks)
An unlabelled bottle contains a colourless solution known to be sodium bromide. Describe how you would confirm the presence of bromide ions using silver nitrate and ammonia solution.

Procedure & Observations:

  • Add dilute nitric acid (\(\text{HNO}_3\)), followed by aqueous silver nitrate (\(\text{AgNO}_3\)). (1 mark)
  • A cream precipitate of silver bromide (\(\text{AgBr}\)) forms. (1 mark)
  • Add dilute ammonia solution: the precipitate does not dissolve. (1 mark)
  • Add concentrated ammonia solution: the precipitate dissolves to produce a colourless solution. (1 mark)