Unit 4: CH04 Syllabus Node

Condensation Polymers (Polyesters & Polyamides)

Condensation polymerisation, Terylene (PET) polyester, Nylon 6,6 and Kevlar polyamides, repeating unit identification, hydrolysis, and polymer disposal for OxfordAQA A-Level Chemistry.

1. Condensation vs Addition Polymerisation

Polymers are giant macromolecules formed by linking thousands of small monomer units together:

Feature Addition Polymerisation (AS Unit 2) Condensation Polymerisation (A2 Unit 4)
Monomer Requirements Monomers contain a carbon-carbon double bond (C=C alkenes). Monomers contain two different functional groups (e.g. -COOH, -OH, -NH2, -COCl).
Byproducts Formed Zero byproducts: 100% atom economy. A small molecule is eliminated at each linkage (usually H2O or HCl).
Polymer Backbone Non-polar, inert carbon-carbon chain (-C-C-C-C-). Polar chain containing ester (-COO-) or amide (-CONH-) linkages.
Biodegradability Non-biodegradable (chemically inert C-C bonds resist bacterial and enzymatic attack). Biodegradable (polar linkages can be slowly hydrolysed by water and environmental enzymes).

2. Polyesters: Terylene (PET)

Polyesters are formed when dicarboxylic acids react with diols (or from hydroxycarboxylic acids containing both groups):

Terylene (Poly(ethylene terephthalate) / PET) Synthesised from benzene-1,4-dicarboxylic acid and ethane-1,2-diol with the elimination of water:
n HOOC-C6H4-COOH + n HO-CH2CH2-OH -> -[CO-C6H4-CO-O-CH2CH2-O]n- + 2n H2O
Applications: Synthetic textile clothing fibres (Terylene/Dacron), plastic beverage bottles, and food packaging trays.

3. Condensation Polymer Repeating Units Diagram

Condensation Polymers: Terylene Polyester and Nylon 6,6 Polyamide Terylene (PET) Polyester Repeating Unit C=O C=O O CH2 - CH2 O ] n Nylon 6,6 Polyamide Repeating Unit CO (CH2)4 CO NH (CH2)6 NH ] n

4. Polyamides: Nylon 6,6 and Kevlar

Polyamides are formed when dicarboxylic acids (or acyl dichlorides) react with diamines (or from amino acids):

1. Nylon 6,6

Formed from hexanedioic acid (6 carbons) and hexane-1,6-diamine (6 carbons):

n HOOC-(CH2)4-COOH + n H2N-(CH2)6-NH2 -> -[CO-(CH2)4-CO-NH-(CH2)6-NH]n- + 2n H2O

The amide links (-CONH-) form extensive intermolecular hydrogen bonds between adjacent polymer chains, giving Nylon high tensile strength, elasticity, and abrasion resistance (ropes, textiles, carpets).

2. Kevlar (High-Performance Aromatic Polyamide)

Synthesised from benzene-1,4-dicarboxylic acid and benzene-1,4-diamine:

n HOOC-C6H4-COOH + n H2N-C6H4-NH2 -> -[CO-C6H4-CO-NH-C6H4-NH]n- + 2n H2O

Why Kevlar is Exceptionally Strong

  • The planar benzene rings make the polymer chains extremely rigid and linear.
  • These straight chains pack together tightly in parallel sheets.
  • Immense numbers of regular intermolecular hydrogen bonds form between C=O and N-H groups on neighbouring chains.
  • This produces an extraordinarily high tensile strength-to-weight ratio: Kevlar is 5 times stronger than steel on an equal-weight basis (used in bulletproof vests, aerospace composites, and puncture-resistant tyres).

5. Polymer Hydrolysis & Disposal

Hydrolysis of Condensation Polymers

Unlike addition polymers, polyesters and polyamides can be chemically cleaved by hydrolysis under reflux:

  • Acid Hydrolysis (hot aqueous HCl):
    Polyester -> original dicarboxylic acid + diol
    Polyamide -> original dicarboxylic acid + diamine salt (e.g. Cl- +H3N-(CH2)6-NH3+ Cl-)
  • Alkaline Hydrolysis (hot aqueous NaOH):
    Polyester -> dicarboxylate salt (e.g. Na+-OOC-R-COO-Na+) + diol
    Polyamide -> dicarboxylate salt + diamine

6. Worked Repeating Unit Calculations

Worked Example 1: Deducing Monomers from a Polyamide Structure
Identify the two monomers required to synthesise the polymer with repeating unit:
-[CO-(CH2)8-CO-NH-(CH2)4-NH]n-

Step 1: Locate the amide linkages:

Break the -CO-NH- bonds to restore the monomer functional groups.

Step 2: Add -OH to carbonyl groups to reform carboxylic acids:

HO-CO-(CH2)8-CO-OH = decanedioic acid (10 carbons).

Step 3: Add -H to nitrogen atoms to reform amines:

H-NH-(CH2)4-NH-H = butane-1,4-diamine (4 carbons).

Worked Example 2: Drawing a Biodegradable Polyester Repeating Unit
Polylactic acid (PLA) is a biodegradable polyester made from 2-hydroxypropanoic acid, CH3-CH(OH)-COOH.
Draw the repeating unit of PLA.

Step 1: Identify reacting functional groups:

The single monomer contains both a carboxyl group (-COOH) and an alcohol group (-OH).

Step 2: Eliminate H2O:

Loss of -OH from -COOH and -H from the alcohol group links monomers via ester bonds.

Step 3: Draw repeating unit with trailing bonds:

-[O-CH(CH3)-CO]n-