1. Continuous Monitoring vs Initial Rate Methods
In OxfordAQA A2 Chemistry (CH03 and Paper 5), reaction rates are evaluated using two distinct experimental methodologies:
Method A: Continuous Monitoring
Tracks how a physical property changes continuously over the entire course of a single reaction run:
- Gas Syringe Collection: Measuring volume of gas evolved (e.g. H2 from Mg + HCl, or CO2 from CaCO3 + HCl) at regular time intervals (every 10 or 15 s).
- Colorimetry: Tracking absorbance of a colored ion or halogen over time.
- Continuous Mass Loss: Placing a reaction flask on an analytical balance to measure mass drop as gas escapes.
Method B: Initial Rate (Clock Reactions)
Measures the time taken for an observable chemical event to occur at the very beginning of the reaction across multiple separate runs with varied concentrations:
- Iodine Clock Reaction: Persulfate oxidising iodide in the presence of fixed thiosulfate and starch, timing the sudden switch from colourless to blue-black.
- Disappearing Cross: Timing sulfur turbidity (RP3).
- Initial Rate: Evaluated at t = 0 before reactant concentrations change appreciably.
2. Continuous Gas Volume Monitoring Protocol
To investigate the reaction between magnesium ribbon and hydrochloric acid:
- Clamp a clean, dry 100 cm3 glass gas syringe horizontally. Push the plunger fully in to read exactly 0 cm3. Check that the plunger moves freely with zero friction.
- Measure 25.0 cm3 of 1.0 mol dm^-3 hydrochloric acid into a conical flask using a volumetric pipette.
- Clean a 5 cm strip of magnesium ribbon with emery paper to remove unreactive magnesium oxide (MgO) surface coating.
- Add the magnesium ribbon to the acid, immediately replace the rubber bung tightly, and start the stopwatch simultaneously.
- Swirl continuously to prevent hydrogen bubbles from adhering to the metal surface.
- Record the gas syringe volume reading every 15 seconds until the volume reaches a constant plateau (reaction complete).
3. Tangent Construction for Initial Rate (t = 0)
Plotting gas volume against time produces a curve with steep initial rise that gradually flattens as reactants are consumed:
2. Draw a long, thin, straight line extending across at least 50% of the graph grid.
3. Construct a large gradient triangle:
Gradient = delta y / delta x = delta V / delta t.4. Units of Initial Rate: cm3 s^-1 (or converted to mol dm^-3 s^-1).
A major source of systematic error in gas syringe experiments is gas escaping into the room during the 1 to 2 seconds between dropping in the magnesium and inserting the rubber bung.
Examiner-Approved Solution: Suspend the magnesium ribbon inside the flask above the acid on a thread held by the bung, or place the magnesium in a small test tube inside the flask, stopper the system, and tip the flask to begin the reaction without opening the system to air.
4. Iodine Clock Reaction (Peroxodisulfate & Iodide)
The standard clock reaction in OxfordAQA Chemistry investigates the oxidation of iodide ions by peroxodisulfate(VI) ions (S2O8^2-):
How the Clock Mechanism Functions:
- A known, constant volume of sodium thiosulfate (Na2S2O3) and starch indicator is included in the reaction mixture.
- As iodine (I2) is generated by the main reaction, it is immediately reduced back to iodide by the thiosulfate scavenger reaction. The solution remains completely colourless.
- The exact moment all thiosulfate is consumed, the very next drop of I2 produced is free to complex with starch, triggering an instantaneous colour switch to blue-black.
- The time taken (t) for the blue-black flash to appear is inversely proportional to the initial rate: Initial Rate ∝ 1 / t.
5. Deducing Reaction Orders & The Rate Equation
To determine the rate equation: Rate = k * [S2O8^2-]^m * [I-]^n, a series of experiments is performed varying one concentration while keeping the other constant, with total volume maintained constant by adding deionised water:
| Experiment | Vol of KI / cm3 | Vol of K2S2O8 / cm3 | Vol of Na2S2O3 / cm3 | Vol of Water / cm3 | Time to Blue-Black (t) / s | Relative Rate (1/t) / s^-1 |
|---|---|---|---|---|---|---|
| 1 | 10.0 | 10.0 | 5.0 | 25.0 | 50.0 | 0.0200 |
| 2 | 20.0 (x2) | 10.0 | 5.0 | 15.0 | 25.0 | 0.0400 (x2) |
| 3 | 10.0 | 20.0 (x2) | 5.0 | 15.0 | 25.0 | 0.0400 (x2) |
Analysis of Data:
- Comparing Exp 1 and Exp 2: [I-] doubles while [S2O8^2-] is constant → Rate doubles (0.0200 → 0.0400). Therefore, the reaction is first order with respect to I- (n = 1).
- Comparing Exp 1 and Exp 3: [S2O8^2-] doubles while [I-] is constant → Rate doubles (0.0200 → 0.0400). Therefore, the reaction is first order with respect to S2O8^2- (m = 1).
- Overall Rate Equation:
Rate = k * [S2O8^2-] * [I-](overall second order).
6. Worked Kinetics Rate Constant Problem
Problem: In an initial rate experiment, when [S2O8^2-] = 0.040 mol dm^-3 and [I-] = 0.060 mol dm^-3, the initial rate of reaction is measured as 1.44 * 10^-4 mol dm^-3 s^-1. The reaction follows the rate equation Rate = k * [S2O8^2-] * [I-].
Calculate the value of the rate constant k and state its units.
Step 1: Rearrange the rate equation for k
k = Rate / ([S2O8^2-] * [I-])
k = (1.44 * 10^-4) / (0.040 * 0.060)
k = (1.44 * 10^-4) / (2.40 * 10^-3) = 0.060
Step 2: Determine units of k
Units of k = (mol dm^-3 s^-1) / ((mol dm^-3) * (mol dm^-3))
Units of k = (mol dm^-3 s^-1) / (mol^2 dm^-6) = mol^-1 dm^3 s^-1
Final Answer: k = 0.060 mol^-1 dm^3 s^-1
7. Practice Exam Questions
Question 1: In the iodine clock reaction, why must the amount of sodium thiosulfate added be kept small and constant in all experiments?
Show Answer & Explanation
Correct Answer: A
The initial rate assumption (Rate ∝ 1/t) is only valid if the timed event occurs before reactant concentrations change appreciably (typically within the first 1-5% of reaction progress). Adding too much thiosulfate delays the endpoint beyond the initial rate region.
Question 2: Why must a gas syringe be clamped completely horizontally during continuous rate experiments?
Show Answer & Explanation
Correct Answer: B
Horizontal alignment ensures that the only force moving the plunger is the pressure of the generated gas, eliminating gravity-induced friction and pressure bias.