IB Chemistry R3.2 R3.2.15
R3.2.15 HL

Electrolysis Calculations

Faraday's laws: relating current, time, charge, and mass deposited.

Key Equations

\[Q = I \times t\]

Q = charge (C), I = current (A), t = time (s)

\[n = \frac{Q}{zF}\]

n = moles of substance, z = electrons per ion, F = 96485 C mol⁻¹

Step-by-Step Method

  1. Calculate charge: Q = I × t
  2. Calculate moles of electrons: n(e⁻) = Q / F
  3. Use stoichiometry (z) to find moles of substance
  4. Calculate mass: m = n × M

Worked Example

Q: A current of 2.50 A is passed through CuSO₄(aq) for 30.0 minutes. Calculate the mass of copper deposited at the cathode.

Step 1: \(Q = 2.50 \times (30.0 \times 60) = 4500 \text{ C}\)

Step 2: Cu²⁺ + 2e⁻ → Cu, so z = 2

\(n(\text{Cu}) = \frac{4500}{2 \times 96485} = 0.02332 \text{ mol}\)

Step 3: \(m = 0.02332 \times 63.55 = \textbf{1.48 g}\)

📋 Exam Tips

  • Always convert time to seconds before calculating Q
  • The value of z depends on the charge on the ion: Cu²⁺(z=2), Al³⁺(z=3), Ag⁺(z=1)
  • F = 96485 C mol⁻¹ is given in the IB data booklet
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