HL Extension
Electrophilic Addition Two-Step Mechanism
At Higher Level you must draw complete curly arrow mechanisms for the two-step electrophilic addition of alkenes with halogens (\(\text{Br}_2\)) and hydrogen halides (\(\text{HBr}\)), proceeding via a carbocation intermediate.
Mechanism: Ethene + HBr
Step-by-Step Explanation
Step 1 (slow):
- The electron-rich π bond of the alkene acts as a nucleophile
- A curly arrow goes from the π bond to the δ+ H in HBr (new C-H bond forms)
- Simultaneously, the H-Br bond breaks heterolytically (curly arrow from bond to Br)
- Products: a carbocation intermediate + Br⁻
Step 2 (fast):
- Br⁻ acts as a nucleophile and donates a lone pair to the positive carbon
- A new C-Br bond forms → final product
Mechanism: Ethene + Br₂
Mechanism
Induced Dipole and Addition Steps
- Step 1: As \(\text{Br}_2\) approaches the \(\text{C}=\text{C}\;\pi\) bond, electron repulsion induces a dipole (\(\text{Br}^{\delta+}-\text{Br}^{\delta-}\)). The \(\pi\) electrons attack \(\text{Br}^{\delta+}\), breaking the \(\text{Br}-\text{Br}\) bond heterolytically → forms a carbocation and \(\text{Br}^-\).
- Step 2: The bromide ion (\(\text{Br}^-\)) attacks the carbocation → forms 1,2-dibromoethane.
Curly Arrow Checklist
Key Insight
Why π Bonds are Vulnerable to Electrophiles
The \(\pi\) bond reacts rather than the \(\sigma\) bond because \(\pi\) electrons reside above and below the internuclear axis, making them more accessible and having lower bond strength (\(\approx 270\text{ kJ mol}^{-1}\)).
Examiner Trap
Electrophilic Addition Mechanism Mistakes
- Carbocation intermediate: Always explicitly draw the intermediate carbocation with its positive charge on carbon.
- Arrow origin: First arrow must start from the \(\text{C}=\text{C}\) double bond, NOT from \(\text{HBr}\).
- Induced dipole: Always mark partial charges (\(\delta+, \delta-\)) on \(\text{Br}_2\).
AQA GCSE & IB Chemistry
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